Tin Stp
Posted May 26, 2010
By admin
how many molecules of H2 are produced by the reaction of tin with 20.0 LHF at STP?
Tin(II) fluoride, formerly found in many kinds of toothpaste, is formed in this reaction:
Sn + 2HF ---> SnF2 + H2
1) how many molecules of H2 are produced by the reaction of tin with 20.0 LHF at STP?
2)How many grams of SnF2 can be made by reactiong 7.42 X 10^24 molecules of HF with tin?
can someone please show me the exations to figure these problems out please??
thank you soo much to anyone that helps!!
20L*1atm=n0.0821*293K
n=.831mole HF
.831moleHF (6.02 x10^23 /1mole HF)=5.00514 x 10^23 molecules
7.24 x 10^24 molecules(1 mole HF/6.02 x 10^23 molecules)=12 moles
12 moles HF(SnF2/2HF)=6 moles SnF2
6 moles SnF2(156.7075 g/1mole SnF2)=940.245g SnF2
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